Use XML, XPATH to extract info from content.xml
Posted: Sun Jul 16, 2023 2:22 pm
Hi,
bitmaps stored in OO document can be extracted by unzipping the document. Their path is an internally given name.
To find out which image belongs to which item in the document the below code snippet lists all images with their name and the path in the zip
Good luck,
ms777
bitmaps stored in OO document can be extracted by unzipping the document. Their path is an internally given name.
To find out which image belongs to which item in the document the below code snippet lists all images with their name and the path in the zip
Good luck,
ms777
Code: Select all
Sub ListStoredImages
oDoc = ThisComponent
'create an XML document from the content.xml
oDomBuilder = createUnoService("com.sun.star.xml.dom.DocumentBuilder")
oDom = oDomBuilder.parse(oDoc.DocumentStorage.getByName("content.xml").Inputstream)
'create an XPATH to search for image nodes, which are direct childs of a frame node
oXPath = createUnoService("com.sun.star.xml.xpath.XPathAPI")
oNL = oXPath.selectNodeList(oDom, "//*[name()='draw:frame']/*[name()='draw:image']" )
for k=0 to oNL.length-1
oItem = oNL.item(k)
sHref = oItem.getAttribute("href")
sName = oItem.ParentNode.getAttribute("name")
print sName + ": " + sHref
'if you want to extract the image data ...
' oPic = oDoc.DocumentStorage.getByName("Pictures").getByName(Replace(sHref, "Pictures/", ""))
' oPic has an InputStream, where you can read the data from
' xray oPic
next k
End Sub