[Solved] Closing parenthesis problem

[r4zoli]

I try to convert a document from docx. to odt with Math objects.
I found one problem which I can't resolve.

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\( r + r_+a\)

works correctly, but I needs + indstead a.
If I use

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\( r + r_+ \)

the closing parenthesis is after a + sign in lower position, not a correct.

Any suggestion?

[RoryOF]

I've never used Math before, but \( r + r_a \) gives me your correct result. You may need to Escape your + if the + (or -) sign is important. Hope that helps.

[r4zoli]

I'm editing a nonprofit magazine, and get an article with lot of math equations, I can not avoid this +.

[floris v]

This bad code seems to work: \( r + r_+ }\), sort of. Definitely a bug.

[keme]

This good code works too.

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\( r + r_"+"\)

Remember that + is an operator, so it's not really surprising that leaving it in a limbo (with parentheses etc as "halfway operands") yields strange results.

That "good code" is not much help if you still have to edit a large number of formulas manually. Sorry that I can't help more.
Too bad Find/replace does not work in Math, and neither in embedded objects. You may need to delve into the nitty gritty of ODF to devise an automated solution.

[floris v]

Of course, so stupid of me not to think of that.

[r4zoli]

Thanks, it works.
I tried lot other tricks not this one.

[RGB]

Note, you do not need the backslash for the brackets:

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(r + r_{"+"} )

will work too.

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left(r + r_{"+"} right)

will work better and

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left(r + r_{{}+{}} right)

even better

[r4zoli]

My further observations:
I get the .docx file with integrals with lower and upper limits, and this r + r_+ math objects, saved as OpenDocument in MS Word 2007 SP3, and the saved the saved math objects scrambled when I opened in AOO 3.4.1
The r +r_+ corrected as suggested by you.
These all problems in MSO needs to be corrected in AOO, I changed it manually, because the document contained only 25 equations.
The integral example:

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 int_t_0^t_2 {Q  \(  t  \)  d t}

created in MSO and it works when I transformed to

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 int csub {t_"0"} csup {t_"2"} Q( t)  d t