I am trying to replace with a Regular Expression some numbers with carriage return (also called paragraph breaks) to nothing but it aint working.
This is examplarily my text:
where I want to eliminate the numbers (these were page numbers, hardcoded ones) but also the carriage returns (such ones done with Return without Space).Blabla
1
blabla
blablablabla
2
blabla blabla
12
blabla
13
basdaf
asdfasd
14
asdfa
I could easily find and replace with nothing the numbers, no problem, but then I have left some empty lines.
In normal RegEx I would go for the hex value, e.g.:
Search with Regex:
Code: Select all
\x0A
Code: Select all
\x0A\d{1,2}
So neither are working \n nor \x00A nor \x000A nor \x0D\x0A - I tried a lot.
I found in some post the $ (which is in normal RegEx just the line end, without any length!) but this is not helping, because I can not eliminate the carriage return, I can just find a line's end.
So how can I find and replace the real carriage return character with regex on Mac OS 10.11.6 and OO 4.1.5?
The digits I easily can find, but only not the carriage return.
The line break (with Space+Retrurn) I can find with \n
Thanks.
frank
PS.: I asked that in a german openoffice forum before and got there the hint to ask here.