Hello,
first let me thank you for your time.
So for a hobby of mine (Pen and Paper Roleplay) I'm creating a spreadsheet to quicken the creation of characters, with requires checking if certain entries have been made.
So I have created a table with 30 rows and 3 columns. Lets call it A1:C30.
So A1:A20 can contain a number, if an entry has been made by the user in a cell somewhere else in the spreadsheet. These entries aren't sorted nummerically. B1:B30 contains the numbers 1-30. For convenience I filled C1:C30 just with 1's. Because thats what I need either a number, for which I can check with a followup formula in another cell (=if(E1>0;"True";"False")).
So if I now in another cell want to search for a certain number in A1:A20, I use the following.
=LOOKUP(B1;A$1:A$20;C$1:C$30)
To make it short: I hope to that the formula produces a 1 if it detects one of the numbers 1-30 in the cells A1:A20.
So far the cells A1 and A10 contain entries, 1 and 6.
Right now I have the formula copied 11 times. Say E1:E11 but all it does produce is 1. For every cell that contains the formula. In E11 the formula is =LOOKUP(B11;A$1:A$20;C$1:C$30) and it produces a 1 (even if delete C11 and turn it blank).
Right now the formula tells me that in the Cells A1:A20 all the individual Numbers 1-11 are contained. A1:A20 only contain a formula only produces a result in A1 and A10, the other cells are empty.
Why?
And what formula would check A1:A20 for the numbers 1-30 (disregarding order) and produce a numerical value?
Of course I could work around this by producing something like:
=IF(A1=1;1;if(A1=2;1;if(A1=3;1;if(A1=4.... but there has to be an easier way.
Again thank you for your time.
[Solved] LOOKUP detects values that aren't there
[Solved] LOOKUP detects values that aren't there
Last edited by Ravel on Thu Apr 19, 2018 8:35 pm, edited 1 time in total.
Apache OpenOffice 4.1.5
Windows 10, 64 Pro
Windows 10, 64 Pro
Re: LOOKUP detects values that aren't there
LOOKUP() needs to have a sorted search vector for it to work correctly. If you just need to know whether B1 is present in the range A1:A20, you can use COUNTIF(). It will return how many times the search criterion appears in the list
will return zero if B1 is not in A1:A20.
Code: Select all
=COUNTIF(A1:A20;B1)
OpenOffice 4.1 on Windows 10 and Linux Mint
If your question is answered, please go to your first post, select the Edit button, and add [Solved] to the beginning of the title.
If your question is answered, please go to your first post, select the Edit button, and add [Solved] to the beginning of the title.
Re: LOOKUP detects values that aren't there
Thank you very much on my way to work right now. Will check this solution in the evening, but it sounds very promising.
Apache OpenOffice 4.1.5
Windows 10, 64 Pro
Windows 10, 64 Pro
Re: LOOKUP detects values that aren't there
menu:Tools>Options>Calc>Calculation...
Regular expressions in formulas = OFF (unless you are sure that you need to match regexes)
Search criteria = and <> must apply to whole cells = ON (otherwise "tax" will be matched in "taxonomy")
and by the way, even with a sorted search vector, LOOKUP does not do what most people expect it to do.
Regular expressions in formulas = OFF (unless you are sure that you need to match regexes)
Search criteria = and <> must apply to whole cells = ON (otherwise "tax" will be matched in "taxonomy")
and by the way, even with a sorted search vector, LOOKUP does not do what most people expect it to do.
Please, edit this topic's initial post and add "[Solved]" to the subject line if your problem has been solved.
Ubuntu 18.04 with LibreOffice 6.0, latest OpenOffice and LibreOffice
Ubuntu 18.04 with LibreOffice 6.0, latest OpenOffice and LibreOffice
Re: LOOKUP detects values that aren't there
Thank you two for your quick help. CountIF worked and allowed me to achieve another function I needed.
Apache OpenOffice 4.1.5
Windows 10, 64 Pro
Windows 10, 64 Pro